Overall, I thought this unit was pretty easy to do. It all made sense to me, with the exception of one type of problem where there were two triangles. I enjoy the trig units because the basic rules all apply.
3c. I solved for one triangle already, here is the other.
180-88.1= 91.9 degree angle A
sin33/14=sin91.9/a side a=25.69
180- 91.9- 33= angle B= 55.1 degrees
Friday, December 21, 2012
Sunday, December 2, 2012
Trigonometry and Unit Circles Test Corrections
I found the concepts in this unit to be relatively easy, with the exception of the one displayed in problem 4. I struggled, however, when it came to memorizing the unit circle. I knew the positives and negatives, but not the exact numbers, which hurt me on question 9.
4.
tan50.57= y/x
x= y/tan50.57
tan70.42=(y+3500)/x
x=(y+3500)/tan70.42
y/tan50.57= (y+3500)/tan70.42
y(tan70.42)= (y+3500)(tan50.57)
y(tan70.42)= y(tan50.57) +4256.42
2.81y= 1.22y +4256.42
1.59y= 4256.42
y=2676.99
+3500
6176.99 feet
8.
secx= -5/3
cos x= -3/5
hypotenuse: 5
adjacent: -3
opposite: -4
sin= -45
tan: 4/3
4.
tan50.57= y/x
x= y/tan50.57
tan70.42=(y+3500)/x
x=(y+3500)/tan70.42
y/tan50.57= (y+3500)/tan70.42
y(tan70.42)= (y+3500)(tan50.57)
y(tan70.42)= y(tan50.57) +4256.42
2.81y= 1.22y +4256.42
1.59y= 4256.42
y=2676.99
+3500
6176.99 feet
8.
secx= -5/3
cos x= -3/5
hypotenuse: 5
adjacent: -3
opposite: -4
sin= -45
tan: 4/3
Monday, November 12, 2012
Angles and Velocity Test Corrections
Overall, I thought this test was very easy. The mistakes I made were based on misreading what the problem was asking or only answering half the question. I understand all the concepts. The problems I got wrong were simple to answer. Here they are:
5b. π/3
7b. π/3
10a. 78 degrees
5b. π/3
7b. π/3
10a. 78 degrees
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